September 23, 2006

Manny, Linger and Charlene

Our group consisted of Manny, Linger and myself. We were given question number one to do which is...



We had to prove if this equation is true or false.

Our group decided that this equation is TRUE


To Prove This:






Common Mistake:

A common mistake would be to use the power to power law


Which would obviously make the equation false


So yeah this what our group came up with. If anyone thinks its wrong or has comments just leave a comment :)

13 comments:

Suzanne said...

I agree that this equation is true. And I like the way you proved it, equalling 10^log as 1. I had put the whole thing in log form to prove it. It's still true either way, we're just thinking of it from different angles, I guess. Anyway, good job :)

M-A-R-K said...

i agree with your answer. i think you guys should explain the base law or something. I remember that if you have a base to the power of the same log base it equals one.

jann said...

Good job with the explaination group 1. Most likely, 10^log is equal to 1. So the answer is true. Nothing more to be said.

lindsay said...

i agree with your answer, which is that it's true. i think i do anyway. good job with the explanation! i didn't think of doing that. =) 10^log = 1!!!

be happy.

anh said...

I didn't know that 10^log equals to 1, so I guessed I learned something. But now knowing that it does equal one your group answer seems to be correct and I agree that the equation is true. I guess as long as you knew the laws of logarithms, you would know that this equation was true.

JessicaJill said...

Nice work you guys. That was simple, fast, and easy to understand. I agree with your group and I also think that people would make that mistake as well.

char__lene said...

i made a mistake people 10log^10 is not one. its "" a^logaX = X "" its a special case .WATCH OUT FOR THE CHANGE.. sry guys...

crystal said...

I also agree with your answer; that it's true. I knew 10^log equals 1. But when I tried plugging it into my calculator it said ERR:SYNTAX. SO I thought I was wrong. Stupid calculator, can't rely on that thing. Then I read your blog and everything was clear. Gotta use my noggin.

ashlynn said...

You guys really did help me. I would have never thought of that. At first, I was confused with the question. I agree with what Anh had said about learning something. This rally helped me guys =)

Manny said...

I just wanted to add that...

In this equation of 10^1og(5+x^2)= 5+x^2
It is saying log on base 10 gives you the power of 5+x^2.
Well since it is on base 10, it is 5+x^2.

Just another way of seeing it.

christian said...

This equation is true, as the group stated. If we have a logarithm with the same base and power, it equals one. This is essential to proving that the equation is true. Good work guys.

charlotte said...

YOu gys are right,we got the same answer. I never knew that a^logaX=X, i actually learn someting knew.
When i tyred to solve if the equation 10^log(5+x^2)=5+x^2 ,is true or false, all i knew is that log(10=1. So i used log form and it was the same thing. The equation is true.

danny said...

From first glance, some people may think that the equation is false, but you guys were able to look further from that and found out it was actually true. I agree with your answer. Although I think you should state that 10^log equals 1. I for one never knew that and found it awesome that it does. I should probably know that, or may have learned it before but forgot. Which ever case it may be, thanks!