The graph of this function is invertible because it passed the horizontal line test.
c) Find f-1(0.45) to 2 decimal places.
Note: To find the value of "f-1(x)", we need to trace it in the calculator. But first, we need to change our calculator setting to "Parametric". It describes what happens to x and y seperately.
i) Press [MODE]
ii) Arrow down to "Func" the arrow right to "Par". Press [ENTER]
iii) Press [Y=] then enter X1T= T.
iv) Enter Y1T= T^3 +0.2T
v) Press [GRAPH]
After entering the function, Press [WINDOW]. You'll see "Tmin","Tmax", "Tstep". Change "Tmin" to -1.5 and "Tmax" to 1.5
Note: "Tstep" is the calculation done by the calculator every pixel. f-1(0.45) is an "input", so we want the "output" of the function. If we trace the graph to x= 0.45, y should equal 0.18 to 2 decimal places.
Additional Problem: Find f-1(0.55)
Solution: Simply arrow right 2 times. You should see x=0.55, y=0.27
Lastly, if there is anything that's not explained properly, please give a comment.
I forgot to mention the method to draw the inverse of a function on the graph. Here are the steps:
i)Press [2nd] then [PRGM]
ii)Press  that says "DrawInv" then press [ENTER].
iii)The command will appear on the home screen. Press [VARS] then arrow right once then press .
iv) Press [Y1] (depends where you entered your function). Press [ENTER]
It should show you the inverse of the function you entered in [Y=].
I would also like to remind everyone that there "might" be a quiz tomorrow or on monday. Be ready.
Thats everything we talked about in class, I think. The next scribe is.... umm.... Christian. (^.^V)