__Chapter 7 pre-Test: Antidiffernetiation__

__Multiple Choice__The multiple choice were pretty much calculator work. I will just list the answers our group got.

**#1) If the definite integral 1S3 (x**

^{2}-1)dx is approximately using the Midpoint Rule with n=4, the error is:(B) 1/24

**#2) If -1Sk (3x**

^{2}-2x)dx=6, then k=?(D) 2

**#3) If 0Sk (sec**

^{2}x)/(1+tanx)dx=ln2, and k>0, then the value of k is:(B) 3.14/4

**#4) Let R be the region in the first quadrant enclosed by the graph of y=xcosx, x=0, y=0, and x=k for 0<(3.14/2). The area of R, in terms of k is:**

(A) ksink+cosk-1

__Open Response____This is where all of us (as a class) just became clueless. We looked at it for a long time and read it over again, but we were not 100% or even 90% sure what to do or where to even begin. We're not sure what that -2 is all about and if it's supposed to be in that missing spot in the table.__

**#1) Let f be a differentiable function such that f " is continous and f and f ' have the values given in the table below.**

**Use the information in the table to evaluate:**

a) 0S2 xf ' (x

15.333...

a) 0S2 xf ' (x

^{2})dx**b)1S3 xf ' (x)dx**

This was the answer our group got (aka manny figured it out :) ).

Well that's it for that class. As a class we are really confused about this section, we feel we're not ready for that test on tuesday. We just need a huge review Mr K., a HUGE review.

Oh the scribe for next class is **ANH** :)

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